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8x^2-39x+20(3x-4)(6x-5)=0
We multiply parentheses ..
8x^2+20(+18x^2-15x-24x+20)-39x=0
We multiply parentheses
8x^2+360x^2-300x-480x-39x+400=0
We add all the numbers together, and all the variables
368x^2-819x+400=0
a = 368; b = -819; c = +400;
Δ = b2-4ac
Δ = -8192-4·368·400
Δ = 81961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-819)-\sqrt{81961}}{2*368}=\frac{819-\sqrt{81961}}{736} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-819)+\sqrt{81961}}{2*368}=\frac{819+\sqrt{81961}}{736} $
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